Answer : The mass of produced will be, 6.16 grams.
Explanation : Given,
Mass of = 14 g
Mass of = 56.70 g
Molar mass of = 100 g/mole
Molar mass of = 36.5 g/mole
Molar mass of = 44 g/mole
First we have to calculate the moles of and .
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 moles of react with 2 mole of
So, 0.14 moles of react with moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of .
As, 1 moles of react to give 1 moles of
So, 0.14 moles of react to give 0.14 moles of
Now we have to calculate the mass of .
Therefore, the mass of produced will be, 6.16 grams.