(If you were not a Brainly robot, you would have seen this formula before,

in any class that would assign you this problem to solve.)

** Charge = (initial charge) · e ^ -(time / RC) .**

In this situation:

0.1 = (1) · e ^ -(.0025 / 2.8R x 10⁻⁶)

Ln of each side: ln(0.1) = -.0025 / 2.8R x 10⁻⁶

Multiply each side

by R R · ln(0.1) = -.0025 / 2.8 x 10⁻⁶

Divide each side

by ln(0.1) = -2.303: R = 0.0025 / (2.303 · 2.8 x 10⁻⁶)

I get ** 387.8 Ω **

## Related Questions

What is the force between two charged objects

It’s proportional to the product of their charges, and

inversely proportional to the square of the distance

between them.

It pulls them together if their charges are opposite.

It pushes them apart if they have the same charge.

I0/4

2. rms magnetic field is inversely proportional to distance, so the new rms magnetic field would be:

B0/2

3. average energy density is inversely proportional to the square of the distance, so the new average energy density is:

E0/4

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-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then

v1 = v2

-4.2 + 2.60t = 5.20

2.60t = 9.40

t = 3.62 s

(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.

(c) The two cars will pass each other when their positions are equal.

x1 = 13.5 – 4.2t + 0.5*2.60t^2

x2 = 8.5 + 5.20t

x1 = x2

13.5 – 4.2t + 1.30t^2 = 8.5 + 5.20t

1.30t^2 – 9.40t + 5.0 = 0

t = 6.65s or t = 0.58 s

——————–

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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a. There is a constant magnetic Feld, which means B is constant, so we can rewrite the change in fux as above.Because ΔA is positive, there will be a negative emf in the loop, corresponding to an induced magnetic momentpointing to the left on the page. The current in the loop will be into the page at the top and out of the page atthe bottom

V=-Δφ/ Δt = -B·ΔA/ Δt

b. As the loop’s radius is increasing, we can think about individual electrons in the wire loop as moving radiallyoutward. We’ll consider one in the top of the loop (which is moving up the page). Using the Lorentz ²orce Law

F=q(~v⇥~B)=qvB(ˆy⇥ˆx)=-qvBˆ

Constant forces pointing into the center of the loop will result in circular orbits (around the wire). Because theforce is pointing into the center of the loop, we know we have positive current at that point (into the page).

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**Answer:**

A. 0.0 joules

**Explanation:**

We can calculate the initial kinetic energy of the car, which is given by:

where m is the mass of the car and v its initial speed. After the collision, the car stops, so its final speed is zero. Therefore, the new kinetic energy of the car will be

This type of collision is called ‘perfectly inelastic collision’, and it occurs when there is the maximum loss of kinetic energy, as in this case. Therefore, the correct answer is

A. 0.0 joules

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