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Triangle PQR is transformed to triangle P’Q’R’. Triangle PQR has vertices P(3, −6), Q(0, 9), and R(−3, 0). Triangle P’Q’R’ has vertices P'(1, −2), Q'(0, 3), and R'(−1, 0). Plot triangles PQR and P’Q’R’ on your own coordinate grid. Part A: What is the scale factor of the dilation that transforms triangle PQR to triangle P’Q’R’? Explain your answer. (4 points) Part B: Write the coordinates of triangle P”Q”R” obtained after P’Q’R’ is reflected about the y-axis. (4 points) Part C: Are the two triangles PQR and P”Q”R” congruent? Explain your answer. (2 points)
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HELP!! 15 POINTS Can someone check my answers? 1. For the data in the table, does y vary directly with X? If it does write an equation for the direct variation.(X,y) (8,11) (16,22) (24,33) Yes y=2.75x Yes y=0.6875x*** Yes y=1.375x No y does not vary directly with X ** (For #1, I’m debating between B and D) 2.for the data in the table, does y vary directly with X? If it does write an equation for the direct variation. (X,y) (16,4) (32,16) (48,36) Yes y=2x Yes y=4x Yes y=8x No y does not very directly with x*** 3. (Time/hour,distance/miles)(4,233) (6,348) (8,464) (10, 580) Express the relationship between distance and time in a simplified form as a unit rate. Determine which statement correctly interprets this relationship. 232 your care travels 232 miles 1/58 your car travels 58 miles in 1 hour*** 58/1 your car travels 58 miles in 1 hour 10 your car travels for 10 hours 4.what is the slope of the line that passes through the pair of points (2,5) and (8,3) 1/3*** -1/3 3 -3 4.what is the slope of the line that passes through the pair of points (-5.2,8.7) and (-3.2,2.7) 2 3*** -2 -3 5. What is the slope of the line that passes through the pair of points (3/2,-2) and (-3,7/3) -27/26 -26/27 26/27*** 27/26 6.write an equation in point slope from for the line through the given point with the given slope (5,2) m=3 Y+2=3(X-5)*** Y+2=3x-5 Y-2=3(X+5) Y-2=3(X-5) 7. Write an equation in point slope form for the line through the given point with the given slope (-3,-5) m=-2/5 Y+5=-2/5(X+3) Y+5=(-2/5) X-3*** Y-5=-2/5(X+3) Y-5=-2/5(X-3) 8. Write an equation in point slope from for the line through the given point with the given slope. (4,-7) m=-0.54 Y+7=-0.54(x-4) Y-7=-0.54x-4 Y+7=-0.54(X+4) Y-7=-0.54(X-4)*** 9. The table shows the height of a plant as it grows. Which equation in point slope from gives the plants height (time,plant height) (2,16)(4,32)(6,48)(8,64) Y-16=8(X-2)*** Y-16=8x-2 Y+16=8(X+2) The relationship is nonlinear 10. Write y=-2/3x+7 in standard form 2x+3y=21 3x-2y=22 -2x-3y=21*** -2x+3y=7 11. Write y=-1/2x+1in standard form using integers X+2y=2 X+2y=-2*** 2x+y=-2 X-2y=2
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