1: There are 10 kids in a race so the number of ways such that they come first , second and third=10×9×8
(since the first place is occupied by any one of the ten students i.e. we have ten choices after occupying first position there are only 9 students left for second position and after occupying second for the third position only 8 choices are left)
2: We have to find the probability such that there is no replacement such that we draw 135.
for the first position we have to find the probability() that ‘1’ comes out of 8 numbers=
similarly for second choice we could not take 1 as there is no replacement
so probability that 3 comes() =
similarly probability that 5 comes at third position() =
hence, probability that 135 is drawn=