For this question, you need to know that the average velocity of a 100m Olympic athlete is 10 m/s before you start solving the equation. The equation is K (energy in Jules) = 1/2 mv^2 (where m is the mass in kg and v the speed in meters per second).
The correct answer is 4000J. To see how I got it, take a look at the attachment.

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Posted in Mathematics

Working alone, it would take Shandra 45 minutes to mow the lawn. To mow the same lawn, also working alone, it would take Kelly 1 hour and 15 minutes. If they work together, the girls believe it will take them 1 hour to mow the lawn. Which best describes the reasonableness of their solution? Their estimate is longer than the time it will actually take: Their estimate is accurate: Their estimate is shorter than the amount of time it will actually take: Their estimate is longer than the time it will actually take:

The correct answer is that their estimate is longer than the time it will actually take.

Explanation:
Since Shandra can mow the entire lawn in 45 minutes, she can mow 1/45 of it in 1 minute.
Kelly mows the entire lawn in 1 hour 15 minutes, which is 75 minutes; this means she mows 1/75 of it in 1 minute.

Using these rates, and letting x be the amount of time it takes, we have the equation
1/45x + 1/75x = 1 (1 represents the entire lawn).

Rather than try to find a common denominator, we can “cancel” the denominators by multiplying everything by them. First multiply everything by 45:
45(1/45x)+45(1/75x)=1*45
1x+45/75x=45.

Now multiply everything by 75:
75(1x)+75(45/75x)=45*75
75x+45x=3375.

Combine like terms:
120x=3375.

Divide both sides by 120:
120x/120=3375/120
x=28.125.

It will take them a little over 28 minutes together, which means their estimate was longer than the actual time.

Posted in Mathematics

A sailboat race course consists of four legs, defined by the displacement vectors A, B, C, and D as the drawing indicates. The magnitudes of the first three vectors are A=6.4 km , B=5.10 km, and C=4.80 km. The finish line of the course coincides with the starting line. Using the data in the drawing, find the distance of the fourth leg and the angle theta.

The first step is to solve the horizontal component using the given values from the problem and the illustration,
horizontal component = 6.4sin(40°) + 5.1sin(35°) – 4.8sin(23°)Then the vertical component is determined,
vertical component = 6.4cos(40°) – 5.1cos(35°) – 4.8cos(23°)

The distance of the fourth leg is calculated using the Pythagorean Theorem,
distance = (h²+v²)^1/2 = 6.35 km

Finally, the angle is computed by applying the inverse tangent function,
theta = tan^-1(v/-h) = 54.42°

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Posted in Mathematics

Consider the surface given by 2x^2+5y^2+z^2=4. The surface is sliced by planes of the form x=a, y=b or z=c for values of a, b, c given below. How do I match the resulting slices (in other words, the corresponding traces) with their correct plots? — Also the slices are: 1. z= 1.5 2. x= 1 3. z=0 4. y=0

This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you’ll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.

(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4
2x^2 + 5y^2 = 1.75
Now you have an ellipse in the z=1.5 plane as your trace.

(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
5y^2 + z^2 = 2
Now you have an ellipse in the x=1 plane as your trace.

(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
2x^2 + 5y^2 = 4
Now you have an ellipse in the z=0 plane as your trace.

(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
2x^2 + z^2 = 4
Now you have an ellipse in the y=0 plane as your trace.

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Posted in Mathematics

Gracie Shay wants to buy a new Hummer in 5 years. Gracie estimates the cost of the Hummer will be \$28,000. If she invests \$12,000 now, at a rate of 6 percent compounded semiannually, she: 1.Will have enough money 2.Will have exactly \$16,000 3.Will have \$18,000 4.Will have \$16,126.80 5.None of these …?

Option 4 – She will have \$16,126.80

Step-by-step explanation:

Given : Gracie Shay wants to buy a new Hummer in 5 years. Gracie estimates the cost of the Hummer will be \$28,000. If she invests \$12,000 now, at a rate of 6 percent compounded semiannually.

To find : Which option she will have ?

Solution :

Using compound interest formula,

Where, A is the amount

P is the principle P=12,000

Compounded semiannually,

r is the rate 6%=0.06

t is the time 5 years

Substitute the value,

The amount she will have \$16126.99.

Therefore, Option 4 is correct.

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Posted in Mathematics

Use linear approximation to estimate 15^.25 …?

A linear approximation of f(x) in a neighborhood of a

f(x) ~ f(a) + f'(a) (x-a)

f(x) = x^1/4

2^4 = 16 i.e. a = 16

f(15) ~ f(16) + f'(16) (15-16)

f'(x) = 1/4 x^(-3/4)

f(15) ~ 2 + 1/4 (16)^-3/4 (-1)

~ 2 – 1/(32) = 1.96875

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Posted in Mathematics

Im totally lost! A sample from a refuse deposit near the Strait of Magellan had 60% of the carbon 14 of a contemporary living sample. Estimate the age of the sample …?

In living matter, the proportion of carbon 14, an isotope of normal carbon 12, is constant. When the
matter dies, the carbon 14 atoms decay into nitrogen 14 with an emission of radiation such that there
will only be half as many carbon 14 atoms every 5570 years. Thus the half-life of carbon 14 is 5570
years. By measuring the emission of radiation, scientists can infer the population of carbon 14 atoms in
similar living matter and estimate when it died.
(a) In charcoal found in an ancient ﬁre pit on Java, the amount of carbon 14 was found to be 1/16 of
that of a living sample of the same size. Estimate the age of the charcoal.
(b) A refuse deposit near the Strait of Magellan was excavated in the 1930’s and dated using carbon
dating methods. Emissions from carbon 14 disintegrations were found to be occurring 60% of that
of a contemporary living sample. Estimate the age of the sample.
(c) If ten percent of a radioactive substance decays in 10 years, what is its half-life?

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